The polynomial of degree 3, P(x), has a root of multiplicity 2 at x = 5 and a root of multiplicity 1 at x=-5. The y-intercept is y = -37.5. Find a formula for P(x). P(x)= = A car was valued at $40,000 in the year 1994. The value depreciated to $12,000 by the year 2003. A) What was the annual rate of change between 1994 and 2003? r= Round the rate of decrease to 4 decimal places. B) What is the correct answer to part A written in percentage form? r= %. C) Assume that the car value continues to drop by the same percentage. What will the value be in the year 2007 ? value $7050 Round to the nearest 50 dollars. Find an equation for the graph sketched below 8+ 7 6 5 4 3 -5-4-3-2-1 1 2 4 5 -+ -2- -3- -4- -5 -6- f(x) = -7- -8- The graph below shows a transformation of y = 2 5- 4 3 -5-4-3-2-1 2 2 3 4 -1 -2 -3 --4- Write an equation for the graph above. y= G K B Match each equation with a graph above a. black (K) | y=2(1.14) y = 3(0.82)* b. blue (B) | y= 3(1.42)* y = 3(1.14)* | y = 3(0.72) c. red (R) d. green (G) e. orange (O) B G If all the graphs above have equations with form y = ab, Which graph has the largest value for b? [Select an answer Which graph has the smallest value for b? Select an answer Which graph has the largest value for a? [Select an answer R + B Match each equation with a graph above. | y=22 a. blue (B) = -22 b. green (G) y = -2-2 c. orange (O) = 2 d. red (R) Match the formula of the exponential function to its graph. Graphs of Exponential Functions -5-4-3-2-1 -1 Formulas for the Graphs a. f(x) = 4 b. f(x)=(4) 5+ 4 3 2 1 c. f(x)= d. f(x)= (+) 2 I 49 -3- -4 5+ 4 3 2 1 -5-4-3-2 -I 2 3 -1 -2- -3- -4 5+ 5+ 4 3 -5-4-3-2-1 2 2 4 -1 -2- -3 -4- Starting with the graph of f(x) = 42, write the equation of the graph that results when: (a) f(x) is shifted 5 units downward. y = (b) f(x) is shifted 3 units to the right. y = (c) f(x) is reflected about the x-axis. y = Question Help: Video Submit Question The graph below shows a transformation of y = 2. 5+ 4 -5-4-3-2-1 3 2 1 V 2 3 4 5 -1 -2 -3- --4- -5+ Write an equation of the form y = A 2 + k for the graph above. y=