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The position of an object as a function of time is given by x=(0.10)t^(3)+(-1.5)t^(2)+(10.0)t+6.0 , whrere x is in meters and t is in seconds.
The position of an object as a function of time is given by
x=(0.10)t^(3)+(-1.5)t^(2)+(10.0)t+6.0
, whrere
x
is in meters and
t
is in seconds. Determine the average acceleration in the
x
-direction between
t=1.0s
and
3.0s
.\
-3.0(m)/(s^(2))
\
2.7(m)/(s^(2))
\
5.3(m)/(s^(2))
\
-1.8(m)/(s^(2))
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