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The position s of a point (in feet) is given as a function of time t (in seconds). s = (1/t)-(1/t^2) (a)Find the second derivative.
The positionsof a point (in feet) is given as a function of timet(in seconds).
s= (1/t)-(1/t^2)
(a)Find the second derivative.
s''(t) =
(2/t^3)(6/t^4)
(b)Calculate the second derivative at timet= 1.5.
s''(1.5) =________?_________
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