The probability that a passenger will attempt to board an airplane with illegal drugs is 0.005 (i.e.P(D)=0.005). Given that a passenger has illegal drugs, the probability that the alarm will sound is 0.97 (i.e.P(AD)=0.97). If a passenger does not have illegal drugs, the probability that the alarm will not sound is 0.95 (i.e.P(AcDc)=0.95).

1. Find the probability that the alarm does not sound given that the passenger is carrying drugs (i.e. findP(AcD)).
2. Suppose a passenger is randomly selected. Find the probability that the alarm sounds when he/she enters security (i.e. findP(A)).