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The problem is an over simplification of the flow of liquid. - A terrain is given as a grid of cells of random elevations. The

The problem is an over simplification of the flow of liquid. - A terrain is given as a grid of cells of random elevations. The grid is always odd sized and is always a square. - A liquid is poured at the central cell. Water can flow only north-south or east-west; not diagnonally. - At the first step, the water level is the same as the central cell. - Water from one cell flows to a neighbouring cell if the level of water is equal to greater than the elevation of the neighbouring cell. - When the water flows to the neighbouring cell, the level of water is maintained. If the water cannot flow to any new cell, the water level rises. - The simulation stops when the water reaches the end of the domain. - The output consists of the domain represented b). and W representing dry and wet terrain.
Below is an example
Input Format
{:{:780416954275
Water level and location of water:
Current water level: 172
...W...
...W...
Current water level
: 174 Reached edge, exiting. Solution:
Output Format
..W...
..WW...
.WW....
.W....
Constraints: First line of the input has dimension n of (nxn) matrix. Followed by the matrix itself as shown below in the sample input. Write a C++/C program

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