The proportion of Americans that like pecans is believed to be 76 %. A candy store owner claims that the real proportion that like pecans is equal to 76 % . They survey 858 Americans, and find that the proportion of their sample that like pecans is 80 % (i.e. p = 0.8). Test the candy store owner's claim, at the o = 0.01 significance level. a. Have the requirements for this test been satisfied? Yes O No (still complete the test anyway, for practice) H - Hypotheses b. The null and alternative hypotheses are O Ho:p = 0.76 O Ho: = 0.76 Ha:p 0.76 Ha: / > 0.76 O Ho:p = 0.76 O Ho: p = 0.76 Ha:p / 0.76 Ha: / /0.76 c. The claim corresponds to the Select an answer d. The test is Select an answer V e. Identify the significance level. D - Distribution and Data f. Identify the sample size. n g- The appropriate distribution for this test is the Select an answer h. calculate the number of degrees of freedom. If this test does not use degrees of freedom, enter 0. df T - Test statistic and p-value i. Calculate the test statistic. Round to 2 decimal places. j- Calculate p-value. Round to 4 decimal places. = amjex-d V - Verdict k. Make a decision. Reject the null hypothesis (and support the alternative hypothesis). O Fail to reject the null hypothesis (and fail to support the alternative hypothesis). I. State your conclusion about the original claim. There is sufficient evidence to support the claim. O There is not sufficient evidence to support the claim. The results are inconclusive. O There is sufficient evidence to reject the claim. There is not sufficient evidence to reject the claim. The results are inconclusive