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The proportion of Canadians with green eyes is 0.5. As part of a study of the genetic basis for skin sensitivity to sunlight, a research

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The proportion of Canadians with green eyes is 0.5. As part of a study of the genetic basis for skin sensitivity to sunlight, a research term collects a simple random sample of 350 Canadians. Answer the following questions to 4 places past the decimal. a) How many people in the sample would you expect to have green eyes? |0.0014 Incorrect. Tries 3/3 Previous Tries b) What is the standard deviation of the sample proportion? (Use the normal approximation from now on). Submit Answer | Tries 0/3 c) What is the probability that the sample proportion will exceed 0.5267? Submit Answer Tries 0/3Question2: A city council is considering drafting legislation related to the exclusion of renters with children. Since implementation will be expensive, they will only consider proceeding if the true proportion of apartments that prohibit children is more than 75 percent. Suppose that out of 125 sampled apartments, 102 exclude renters with children. 1) What is the observed proportion of apartments which exclude renters with children? O 0.750 O 0.816 O 0.184 1.226 Unknown Submit Answer Incorrect. Tries 1/2 Previous Tries 2) What is the true proportion of apartments which exclude renters with children? O 0.750 O 0.816 O 0.184 O 1.226 O Unknown Submit Answer Tries 0/2 3) Compute the standard error of the observed proportion. O 0.03837 O 0.03466 O 0.00147 O 0.00120 O 0.01470 Submit Answer Tries 0/2 4) Find the 95 percent confidence interval for the true proportion of apartments which exclude renters with children. O (0.544,1.213) O (0.727,0.905) (0.759,0.873) O (0.748,0.884) O (0.814,0.818) Submit Answer Tries 0/25) Is the 99 percent confidence interval wider or narrower than the 95 percent confidence interval? O Narrower O Wider O The same O Not enough information Submit Answer Tries 0/2Questioa: For question 2, test the hypothesis that the true proportion of apartments which exclude renters with children is greater than 75 percent. 1) What is the null hypothesis? 0 po_75 O [3 net equal to 0.75 Submit Answer -Tries 1/2 Previous Tries 2) What is the alternative hypothesis? 0 p0.75 O p nut equal to 0.75 Submit Answer Tries 012 3) Compute the value for the test statistic. O 0.066 O 4.423 O 0.042 O 1.704 O 0.756 Submit Answer Tries 012 4) Compute the Pivalue. O 0.01 O 0.04 O 0.08 O 0.92 O 0.96 Submit Answer Tries 0/2 5) Would you reject the null hypothesis at significance level 0.01? O YES O NO O NOT ENOUGH INFORMATION Submit Answer Tries 0/1 6) Suppose the test statistic in a similar study conducted elsewhere was found to be 4.21. Would you reject the null hypothesis at significance level 0.01? O YES O NO O NOT ENOUGH INFORMATION Submit Answer Tries 0/1

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