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The radial probability density of finding an electron in the 2s orbital in a Hydrogen-like atom a distance s from the nucleus is proportional to:

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The radial probability density of finding an electron in the 2s orbital in a Hydrogen-like atom a distance s from the nucleus is proportional to: 2s P(r) & rR25 (r)]2 where R28 (r) is the radial part of the wavefunction of the Hydrogen-like atom in the 2s state. It turns out that to find the most likely radial position of the electron in the 2s state of the hydrogen like atom, it is sufficient to find the point where the function rR2s(r) has a MINIMUM (You can convince yourself of this by sketching both rR2s(r) and P(r)). Zr Zr2 - 200 Given that rR2s(r) & (r -)e 200 where Z is the nuclear charge, and do is the Bohr radius, find the most probable distance of the electron from the nucleus for the electron in the 2s state in the U91+ ion. Express your final answer in units of the Bohr radius ao. In other words, if you get a final answer that is 2.3 times ao, enter 2.3 as your final

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