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The radionuclide C decays according to CB+e+v: T = 20.3 min 1/2 The maximum energy of the emitted positron is 0.960 MeV. Given the
The radionuclide "C decays according to "C"B+e+v: T = 20.3 min 1/2 The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m("C)=11.011434 u and m("B)=11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted
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Fundamentals of Physics
Authors: Jearl Walker, Halliday Resnick
10th Extended edition
978-1118230718, 111823071X, 978-1118230725
