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The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6 : 1. If one molecule of the above compound

The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6 : 1.
If one molecule of the above compound ( CxHyOZ ) contains half as much oxygen
as required to burn one molecule of compound CXHY completely to CO2 and H2O.
The empirical formula of compound CxHyOz is :
(a) C2H4O
(b) C3H4O2
(c) C2H4O3
(d) C3H6O3

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