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The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6: 1. If one molecule of the above compound

The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6: 1. If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO and HO. The empirical formula of compound CxHyOz is: (1) C3H6)3, (2) CH4O (3) C3H4O2 (4) CH4O3

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