The scalar projection of y on a is the length that y points in space spanned by a. It can be computed as x . y a = I1 2C In order to actually project y onto the space spanned by , you can multiply the scalar projection times a normalised version of a to find the vector projection of y on a: ac . y p = a- -. Let y = [ ] and x = [;] Find the scalar projection of y on x. Number Find the vector projection of y on a. Enter each coordinate of the vector in order. Number Number Draw a picture of all four vectors and verify that p and y - p are orthogonal to one another. The fact that y - p is perpendicular to p implies that y - p is the smallest distance from y to x. Now let u ] and & = Find the scalar projection of u on v. Number Find the vector projection of u on v. Number Number Number