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The sequence {a_(n)} is defined by a_(1)=2 , and a_(n+1)=(1)/(2)(a_(n)+(2)/(a_(n))) for n>=1 . Assuming that {a_(n)} converges, find its limit. lim_(n->infty )a_(n)= Hint:
The sequence
{a_(n)}
is defined by
a_(1)=2
, and\
a_(n+1)=(1)/(2)(a_(n)+(2)/(a_(n)))
\ for
n>=1
. Assuming that
{a_(n)}
converges, find its limit.\
\\\\lim_(n->\\\\infty )a_(n)=
\ Hint: Let
a=\\\\lim_(n->\\\\infty )a_(n)
. Then, since
a_(n+1)=(1)/(2)(a_(n)+(2)/(a_(n)))
, we have
a=(1)/(2)(a+(2)/(a))
. Now solve for
a
.
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