The sine of \(45^\circ\) should not be over \(y\) if the angle of depression for Alice is \(60^\circ\). It was a mistake in the setup of the problem. Explanation: In the Law of Sines, each side of a triangle is related to the sine of its opposite angle. If Alice's angle of depression to the bird is \(60^\circ\), then the side opposite this angle (the distance from Alice to the bird, \(y\)) should be paired with \(\sin(60^\circ)\), not \(\sin(45^\circ)\). The correct setup should be: \[ \frac{y}{\sin(60^\circ)} = \frac{10}{\sin(45^\circ)} \] This means that the distance \(y\) from Alice to the bird is related to the sine of her angle of depression, \(60^\circ\), and the known distance from Bob to the bird (10 meters) is related to the sine of his angle of depression, \(45^\circ\). This ensures that each side of the triangle is correctly paired with its corresponding angle. i was talinkg about this one