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The solution to the differential equation d2 y dy 10 - + 25y = 0;y = 2 and dy = 14 when t = 0
The solution to the differential equation d2 y dy 10 - + 25y = 0;y = 2 and dy = 14 when t = 0 dt 2 dt dt is a. y = 20-5t + 405t b. y = 2e-St + 40-5t C. y = 2est + 4test d. y = 2e-St + 4te-5t
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