The speed of a falling skydiver is so) = 52 (1 34/3) in metres per second] where t is the number of seconds since leaving the plane. Then the terminal velocity is L = lim t) : | | _ t+oo The distance |'u (t) L| can be simplied, as a function of t, to| '@ Q. So the time it takes (to the nearest second} for the skydiver . to get within metres per second of the terminal velocity is l | seconds - to get within 10300 metres per second of the terminal velocity is| | seconds. Note: the Maple syntax for e: is ezpr)