The steel beam is 3600 mm long and has a weight of 3078.05556 Newtons; the center-of-gravity of the beam (without the man) is located at the center of the beam, given by the Point G of the figure. The man weighs 785 Newtons. The diameter of the pulley, D = 450 mm. The rope passes through a hole in the beam, and the man pulls on the rope with a force, T = 400 Newtons. (Thus the tension in the rope is everywhere T 400 Newtons.) The pin at Point A is welded, and thus the support at this point should be considered fixed; that is, it will generate a reaction force and moment. 1. Draw a free-body diagram (FBD) which is suitable for solution of this problem. You must draw a separate diagram and you may NOT use the exisiting figure given here. In your FBD, it is essential that you make clear precisely what object or collection of objects actually defines you "free body". Your FBD must clearly/correctly show all reactions at the support, Point A, in addition to the applied loads. You must include the weight of the beam and the weight of the man. The FBD should define the positive "x" and "y" directions, and include the dimensions necessary for computing moments. 2. Write the equations of equilibrium and solve for the reactions at Point A. You must be clear in your results with respect to the direction in which the reactions act on the body. Express force(s) in Newtons (N) and moment(s) in Newton-mm or Newton-meters (N-m). Welded pin Weight of man: 785 Newtons Weight of beam: 3078.05556 Newtons Tension in rope: 400 Newtons 1800 mm 900 D D=450 mm (Pulley Diameter) mm