The stoichiometry of reaction being CaCO$3$ : CO$2=1$:$1,$ molecules of CaCO$3$ is $0\mathrm{.}001$ mol. The mass of antacid is $0\mathrm{.}2482$g$.$ The molecular weight of CaCO$3$ is $100\mathrm{.}0869$ g$/$mol$.$ What is the mass of CaCO$3$ in the antacid?