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The summit of a mountain, 2450 m above base camp, is measured on a map to be 4580 m horizontally from the camp in a

The summit of a mountain, 2450 m above base camp, is measured on a map to be 4580 m horizontally from the camp in a direction 38.4 west of north. What are the components of the displacement vector from camp to summit?What is its magnitude? Choose the x axis east, y axis north, and z axis up.Here is how I was explained to do it. However I am still wondering why sin used for x and cos for Y when it is usually the other way around for vectors.

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North * X component is west of North so it is negative 4580m * y component is North Jo it is positive 32.40 2450 m * Zaxis is up west X East * Note X now has X= - 4580 sin (38.40) =-2845m sin and y now has South y = 4580 cos ( 38. 40) = 3589m cos 2 = 2450 m * = (-2845 m, 3589m, 2450m) 121 = 1 (- 28451 2 + ( 3589) 2+( 2450)2 5190 m

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