The switch S in the RL circuit shown above is closed at time two. R = B ohms; L = 6 H; and e - 12 V. Find the following values at the specified times, Voltage across resistor: VR = |0 Volts Voltage across inductor VL - -12 * Volts Current in the circuit I'm 0 Amps t=2 time constants Voltage across resistor: VR = 11:168 X Volts Voltage across inductor: VL = 0.83 X Volts Current in the circuit: I = 1.396 * Amps Energy stored in the inductor: 5.85 X 1