Question
The TAB_BIRTHDAY table consists of every day of the year, from January 1 to December 31, along with a ranking based on how many babies
The TAB_BIRTHDAY table consists of every day of the year, from January 1 to December 31, along with a ranking based on how many babies were born in the United States on that date between 1973 and 1999. Rank 1 is the most popular, rank 2 is the next most popular, and so forth. Create and populate the TAB_BIRTHDAY table by using the following SQL statements. CREATE TABLE tab_birthday (BIRTHDAY_MONTH NUMBER, BIRTHDAY_DAY NUMBER, BIRTHDAY_RANK NUMBER); / INSERT INTO tab_birthday SELECT * FROM hchen.tab_birthday; / COMMIT; / SELECT COUNT(*) FROM tab_birthday; / Write a PL/SQL anonymous block that accepts an integer n (n = 1 or n = 2) from the user input and 1) displays five (5) most popular birthdays along with the ranks for each month if the user input is 1 (n = 1), or 2) displays five (5) least popular birthdays along with the ranks for each month if the user input is 2 (n = 2). Sort your output in ascending order by months, and then most/least popular birthdays. You will lose 10 points if the title lines are missing in your output. You will lose 10 points if your output is not in the correct format. For example, you must display the birthdays and ranks for the same month in one line. Each day-rank pair must be displayed in the DD/RRR format (2-digit day and 3-digit rank) (e.g., 03/088). You may hard-corded values of months (e.g., FOR idx IN 1..12 LOOP). If you have hard coded the birthdays or ranks (e.g., DBMS_OUPT.PUT_LINE('1 <20> <14>')) in your PL/SQL block, you will receive 0 points. To avoid complicating issues, you can assume that the user always enters input from keyboard that consists only of the digits 0 through 9 and Enter. This question can be solved without using cursors.
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