The TikTok is Not Real Life Company has decided to hire you to improve their board game simulator for the game "Chutes & Ladders". The board has squares which are numbered from $1$ to $100$ and players have counters which start on the theoretical square $0.$ The players take turns at spinning a spinner with the numbers $1$ to $6$ on it$,$ and each moves his or her counter forward the number of squares corresponding to the number on the spinner. The first person to reach square $100$ is the winner.

The interest is caused by the fact that pairs of squares are connected together by "ladders" $($which connect a lower$-$numbered square to a higher$-$numbered square$)$ and "chutes" $($which run from high to low$).$ If a counter lands on the start of a chute or ladder the counter is moved to the corresponding square at the end of the chute or ladder. Note that landing on the end square of a ladder or a chute has no effect, only the start square counts. If a player is on square $95$ or higher, then a spin which takes them past $100$ must be ignored $-$ thus a player on square $99$ must ignore all spins which are not $1.$

In C$++,$ using classes and arrays of classes:

Create a Chutes & Ladders game for two $(2)$ to six $(6)$ players, allow the users to play as many games as they wish, either with the same players or new ones

Use two classes:

The game: stores information about the board $($in an array$)$; methods include a constructor $($sets up all the chutes & ladders values$),$ a turn method $($requires a player$),$ a spin method $($returns a random number from $1$ to $6),$ and a winner method $($returns a bool indicating whether this player has won or not$)$

The player: stores information about the player; methods include all relevant accessor and mutator methods. Track how many chutes or ladders the player has reached while playing the game. Output this information for the winner.

Main will request the number of players and get the names for that number of players. Be sure to restrict the number of players to a number from two $(2)$ to six $(6).$ Main will determine who goes first and turns continue in round$-$robin fashion after that.