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The variable values are right now located in the following registers: a in s0, and b in s1 . Using ONLY the add instruction ,

The variable values are right now located in the following registers: a in s0, and b in s1. Using ONLY the "add" instruction, write a piece of a MIPS assembly code that performs the following computation:

a = 65 * b

Hint 1: use the fact that 65=64+1, since 64 is a power of 2.

Hint 2: the MIPS register $zero might be useful. This question/a similar one has already been answered, but is there any OTHER way than just adding a, b 65 times?

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