The velocity of particle A, t seconds after its release is given by Va (t) = 2.7 e 0.8 meters per second. The velocity of particle B, t seconds after its release is given by Vp(t) = 13.5t - 0.31" meters per second. If velocity is measured in meters per second, how much farther does particle A travel than particle B during the first ten seconds (from t = 0 to t= 10)? Round to the nearest meter. . . . O A. 9,486 m O B. 9,682 m O-C. 9,482 m O D. 9,382 m