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The vertices of a triangle are at the points (1, 0, -1), (3, -1, -5), and (4, 2, 0).Find the area of the triangle. Hint:

The vertices of a triangle are at the points (1, 0, -1), (3, -1, -5), and (4, 2, 0).Find the area of the triangle.

Hint: the area of the triangle will be one-half the area of the parallelogram formed one two sides by the corresponding two sides of the triangle.

Don't forget Sakai is a bit tricky.If your answer involves a fraction, e.g. four-thirds, express it as 4/3.If you answer involves a number to a power or square root express a number squared, e.g. 72, as 7^2 or the square root of 7 as 7^0.5.Put it all together as 4/3(7^0.5).

The area of the triangle is:

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