Theorem: For any real number $x,x+|x-5|5$

In a proof by cases of the theorem, there are two cases. One of the cases is that $x>5.$

What is the other case?

$x0$

$x<mn\; id="EditorElement\_26330">0</mn>$

$x<mn\; id="EditorElement\_26314">5</mn>$

$x5$