there are some mistake, Q2 refers to Q1 answer for further calculation.

Q2 (10 POINTS) a) Follow from Q2, if the cost of electricity is $1.1/kWh, and the cost of the solar panel is $15,000 per m, calculate the Return of Investment in years b) If the inverter and other associated electronic parts cost $1500/kW, calculate again the Return of Investment in years . Q1 (20 POINTS) A solar panel is of area 30 m' and efficiency 22%. Estimate the maximum power received (in kW) when the panel is always adjusted to normal to the sun. Assume the average number of hours of sunlight is 4.2 hours. (The 4.2-hour has been accounted for the sun variation during a day and a year), calculate the energy received for a year (in kWh). Use 1360W/m as the solar constant and you may assume AM#=1 for max power condition. Q2 (10 POINTS) Q1 a) Follow from O2, if the cost of electricity is $1.1/kWh, and the cost of the solar panel is $15,000 per m, calculate the Return of Investment in years b) If the inverter and other associated electronic parts cost $1500/kW, calculate again the Return of Investment in years Q2 (10 POINTS) a) Follow from Q2, if the cost of electricity is $1.1/kWh, and the cost of the solar panel is $15,000 per m, calculate the Return of Investment in years b) If the inverter and other associated electronic parts cost $1500/kW, calculate again the Return of Investment in years . Q1 (20 POINTS) A solar panel is of area 30 m' and efficiency 22%. Estimate the maximum power received (in kW) when the panel is always adjusted to normal to the sun. Assume the average number of hours of sunlight is 4.2 hours. (The 4.2-hour has been accounted for the sun variation during a day and a year), calculate the energy received for a year (in kWh). Use 1360W/m as the solar constant and you may assume AM#=1 for max power condition. Q2 (10 POINTS) Q1 a) Follow from O2, if the cost of electricity is $1.1/kWh, and the cost of the solar panel is $15,000 per m, calculate the Return of Investment in years b) If the inverter and other associated electronic parts cost $1500/kW, calculate again the Return of Investment in years