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There is 2.90 eV!! Also, h = 6.626*10^-34 J*S D. If a 397 nm photon hits the surface of calcium, calculate the maximum kinetic energy

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There is 2.90 eV!!

Also, h = 6.626*10^-34 J*S

D. If a 397 nm photon hits the surface of calcium, calculate the maximum kinetic energy (in eV) of the emitted photoelectron

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