THERE IS A FLAW IN THIS SOLUTION. It is not right. Please find the flaw, tell me what it is AND HOW TO FIX IT!!

1. A 55-kg child, sledding down a hill that is at an angle of 35* from the horizontal, experiences a force of kinetic friction of magnitude 65 N. The child's speed is 3.0 m/s near the top of the hill. Determine the speed after the child has traveled 50.0 m downhill. Air resistance is negligible. Whotal = Food cos + Frad Cost Whotal = my and coser+ Fad cost Weral = (55) (9.81) (50. 0) (0535 + 165)(50-0) Cos 120 m = 55 kg WHotel = 22098. 67 - 3250 FX = 65 N W total = 18 848. 67 Vi = 3.Omls 3 4d = 50.0m to the child's speed @ V 1 = ? the bottom of the hill is 18 848. 67 = mur?_ my-2 20mls 2 OF = 180' Fx TVad 2 18 848. 67 = (35) Vr - 155) (3) Org = 350 2 2 18 848. 6 7 + 247 . 5 = 27. 5 V/2 19096. 17 27.5 26.35 = VF