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Therefore, it is an excellent approximation to write qrot (T) as 9rot (T) = ( 23 + 1)e - 10 )(+1)/ dJ This integral is

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Therefore, it is an excellent approximation to write qrot (T) as 9rot (T) = ( 23 + 1)e - 10 )(+1)/ dJ This integral is easy to evaluate because if we let x = J(J + 1), then dx = (2J + 1)d J and q(T) becomes 9rot (T) = e 0 T =

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