Thermodynamics:

Calculate (can be done in a spreadsheet) the equilibrium constant for quartz from 5-100 degrees C at five-degree increments using the Van't Hoff equation

Find the blanks of gibbs free energy, log K, PK, and H_r of quartz

Then plot the results Log10 (KT) (ordinate) vs temperature (abscissa)

What do these results mean?

AG" log KPK , . Component AG: (Drever, App II) kJ/mol H4S104 -1307.9 quartz -856.3 water -237.14 -1457.3 -910.7 -285.83 van't Hoff, quartz, 5-100C LogK, -log K. + AH,/R/In(10) * (1/T, - 1/T.) quartz, 25 -3.00 -3.50 Quartz log K dH t, C log Kit (qtz) 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 logk (quartz) -4.00 -4.50 0 50 100 150 Temperature, C AG" log KPK , . Component AG: (Drever, App II) kJ/mol H4S104 -1307.9 quartz -856.3 water -237.14 -1457.3 -910.7 -285.83 van't Hoff, quartz, 5-100C LogK, -log K. + AH,/R/In(10) * (1/T, - 1/T.) quartz, 25 -3.00 -3.50 Quartz log K dH t, C log Kit (qtz) 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 logk (quartz) -4.00 -4.50 0 50 100 150 Temperature, C