Given the Enthalpy-pressure graph for refrigerant R123, ?Evaporator Temperature = 5C , Condenser Temperature

Pressure [bar] 40 30 Solkane 123 20 .10 9.0 .U 1.0 6.0 5.0 4.0 3.0 2.0 100000 6441as0 U.8 0.6 0.5 0.4 0.3 0.2 0.10 U.Uy U.08 0.07 0.06 0.05 0.04 170 Isotherm [C] Isochor [m/kg] Isentrop [kJ/kgK] SOLVAY 190 210 - 230 250 270 290 310 Group 1 Cycle 2. Evaporator temperature = 5 C, Condenser temperature = 35 C. R 123 - 350 370 Enthalpy [kJ/kg] Assume all cycles are ideal, calculate the Cycle coaling capacity compressor input - 330 power 160 150 390 410 20 430 450 4 0045 470 490 0.0080 0014 1016 X 0030 -0040 Std 0070 URE Bet 510 530