Question
these answers are all wrong i need the correct sql command please. below is the schema. (LocationNum DECIMAL (2,0) PRIMARY KEY, LocationName CHAR(25), Address CHAR(25),
these answers are all wrong i need the correct sql command please. below is the schema.
(LocationNum DECIMAL (2,0) PRIMARY KEY, LocationName CHAR(25), Address CHAR(25), City CHAR(25), State CHAR(2), PostalCode CHAR(5) ); CREATE TABLE CondoUnit (CondoID DECIMAL(4,0) PRIMARY KEY, LocationNum DECIMAL (2,0), UnitNum CHAR(3), SqrFt DECIMAL(5,0), Bdrms DECIMAL(2,0), Baths DECIMAL(2,0), CondoFee DECIMAL(6,2), OwnerNum CHAR(5) ); CREATE TABLE Owner (OwnerNum CHAR(5) PRIMARY KEY, LastName CHAR(25), FirstName CHAR(25), Address CHAR(25), City CHAR(25), State CHAR(2), PostalCode CHAR(5) ); CREATE TABLE ServiceCategory (CategoryNum DECIMAL(4,0) PRIMARY KEY, CategoryDescription CHAR(35) ); CREATE TABLE ServiceRequest (ServiceID DECIMAL(4,0) PRIMARY KEY, CondoID DECIMAL(4,0), CategoryNum DECIMAL(4,0), Description CHAR(255), Status CHAR(255), EstHours DECIMAL(4,2), SpentHours DECIMAL(4,2), NextServiceDate DATE ); sqlite> .schema CREATE TABLE Location (LocationNum DECIMAL (2,0) PRIMARY KEY, LocationName CHAR(25), Address CHAR(25), City CHAR(25), State CHAR(2), PostalCode CHAR(5) ); CREATE TABLE CondoUnit (CondoID DECIMAL(4,0) PRIMARY KEY, LocationNum DECIMAL (2,0), UnitNum CHAR(3), SqrFt DECIMAL(5,0), Bdrms DECIMAL(2,0), Baths DECIMAL(2,0), CondoFee DECIMAL(6,2), OwnerNum CHAR(5) ); CREATE TABLE Owner (OwnerNum CHAR(5) PRIMARY KEY, LastName CHAR(25), FirstName CHAR(25), Address CHAR(25), City CHAR(25), State CHAR(2), PostalCode CHAR(5) ); CREATE TABLE ServiceCategory (CategoryNum DECIMAL(4,0) PRIMARY KEY, CategoryDescription CHAR(35) ); CREATE TABLE ServiceRequest (ServiceID DECIMAL(4,0) PRIMARY KEY, CondoID DECIMAL(4,0), CategoryNum DECIMAL(4,0), Description CHAR(255), Status CHAR(255), EstHours DECIMAL(4,2), SpentHours DECIMAL(4,2), NextServiceDate DATE );
List the number of bedrooms and average condo fee by bedrooms for condo units that are larger than 700 square feet and the average condo fee is less than $500.00. Sort the results by the average condo fee.
Your Answer: wrong
SELECT COUNT(Bdrms), AVG(CondoFee)
Group by Bdrms
having sqrft > 700 AND
AVG(CondoFee) < 500
OrderBy AVG(CondoFee);
List the condo id and description for every service request that contains "kitchen" in the description.
Your Answer:
SELECT CondoID, Description
FROM CondoUnit, ServiceRequest
WHERE CondoUnit.CondoID = ServiceRequest.CondoID
AND ServiceRequest.Description = 'Kitchen';
List the location number, average square footage, and average condo fee at each location.
Your Answer: wrong
SELECT locationNum, avg(sqrFt) AverageSquareFeet, avg(CondoFee)
FROM Location, CondoUnit
WHERE location.locationNum = CondoUnit.locationNum;
For every service request, list the last name and first name of the owner and the category and description of the service. Sort the results by service category.
Your Answer:wrong
SELECT lastName, FirstName, CategoryNum, Description FROM
Owner, ServiceRequest, CondoUnit
WHERE Owner.ownerNum = CondoUnit.OwnerNum AND
ServiceRequest.CondoID = CondoUnit.COndoID
AND OrderBy CategoryNum;
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