This assignment requires you to write an LC-3 assembly language routine leading to being able to transform a string of digits (and + and - signs) into both the corresponding integer and the 16-bit floating point value

This program shifts a number 11 places to the left, then ANDs the answer with b0111100000000000. This means the answer can only have 1s in bits 14 to 11. The answer is then written to display like the diagram below:

Call the program part3.asm. The number to use must be stored at a label called number and the program begins with:

If the number is b0000000000011011 the output should be: 0 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0

LC3 Console ter an integer between -511 and +511: 400 e input is invalid. ter an integer between-511 and +511: 12345 he input i3 invalid. ter an integer between-511 and +511: +12345 e input i3 invalid. ter an integer between -511 and +511: -512 The input is invalid. nter an integer between-511 and +511: +511 Halting the processor-- nter an integer between -511 and +511: +0 Halting the processor nter an integer between-511 and +511: -1 Halting the processor-- Enter an integer between -511 and +511:-511 111 1 11 00000000 1 Halting the processor - This is the display for the output, except instead of 000000000000000 0 as the output when the number is +0, the output should be 01011000 00000000 when the number is b0000000000011011 LC3 Console ter an integer between -511 and +511: 400 e input is invalid. ter an integer between-511 and +511: 12345 he input i3 invalid. ter an integer between-511 and +511: +12345 e input i3 invalid. ter an integer between -511 and +511: -512 The input is invalid. nter an integer between-511 and +511: +511 Halting the processor-- nter an integer between -511 and +511: +0 Halting the processor nter an integer between-511 and +511: -1 Halting the processor-- Enter an integer between -511 and +511:-511 111 1 11 00000000 1 Halting the processor - This is the display for the output, except instead of 000000000000000 0 as the output when the number is +0, the output should be 01011000 00000000 when the number is b0000000000011011