Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

This code comes from the Object-Oriented Data Structures Using Java Third Edition. Question: Modify the Sorts.java program to compare the different sorting algorithms. You need

This code comes from the Object-Oriented Data Structures Using Java Third Edition.

Question: Modify the Sorts.java program to compare the different sorting algorithms. You need to add code to allow the user to choose the different sorting algorithm, change the size of the testing data, record and output the time used by the chosen algorithm in milliseconds.

Data Sizes:

Selection and insertion sorts - use the 10K, 20K, 30K, 40K, 50K, 60K, 70K, 80K, 90K data set.

Insertion sort with sorted data - use the 10K, 20K, 30K, 40K, 50K, 60K, 70K, 80K, 90K data set

Merge and quick sorts - use the 100K, 200K, 300K, 400K, - 500K data set

Programs:

//---------------------------------------------------------------------------- // Sorts.java by Dale/Joyce/Weems Chapter 10 // // Test harness used to run sorting algorithms. //---------------------------------------------------------------------------- import java.util.*; import java.text.DecimalFormat; public class Sorts { static final int SIZE = 50; // size of array to be sorted static int[] values = new int[SIZE]; // values to be sorted static void initValues() // Initializes the values array with random integers from 0 to 99. { Random rand = new Random(); for (int index = 0; index < SIZE; index++) values[index] = Math.abs(rand.nextInt()) % 100; } static public boolean isSorted() // Returns true if the array values are sorted and false otherwise. { boolean sorted = true; for (int index = 0; index < (SIZE - 1); index++) if (values[index] > values[index + 1]) sorted = false; return sorted; } static public void swap(int index1, int index2) // Precondition: index1 and index2 are >= 0 and < SIZE. // // Swaps the integers at locations index1 and index2 of the values array. { int temp = values[index1]; values[index1] = values[index2]; values[index2] = temp; } static public void printValues() // Prints all the values integers. { int value; DecimalFormat fmt = new DecimalFormat("00"); System.out.println("The values array is:"); for (int index = 0; index < SIZE; index++) { value = values[index]; if (((index + 1) % 10) == 0) System.out.println(fmt.format(value)); else System.out.print(fmt.format(value) + " "); } System.out.println(); } ///////////////////////////////////////////////////////////////// // // Selection Sort static int minIndex(int startIndex, int endIndex) // Returns the index of the smallest value in // values[startIndex]..values[endIndex]. { int indexOfMin = startIndex; for (int index = startIndex + 1; index <= endIndex; index++) if (values[index] < values[indexOfMin]) indexOfMin = index; return indexOfMin; } static void selectionSort() // Sorts the values array using the selection sort algorithm. { int endIndex = SIZE - 1; for (int current = 0; current < endIndex; current++) swap(current, minIndex(current, endIndex)); } ///////////////////////////////////////////////////////////////// // // Bubble Sort static void bubbleUp(int startIndex, int endIndex) // Switches adjacent pairs that are out of order // between values[startIndex]..values[endIndex] // beginning at values[endIndex]. { for (int index = endIndex; index > startIndex; index--) if (values[index] < values[index - 1]) swap(index, index - 1); } static void bubbleSort() // Sorts the values array using the bubble sort algorithm. { int current = 0; while (current < (SIZE - 1)) { bubbleUp(current, SIZE - 1); current++; } } ///////////////////////////////////////////////////////////////// // // Short Bubble Sort static boolean bubbleUp2(int startIndex, int endIndex) // Switches adjacent pairs that are out of order // between values[startIndex]..values[endIndex] // beginning at values[endIndex]. // // Returns false if a swap was made; otherwise, returns true. { boolean sorted = true; for (int index = endIndex; index > startIndex; index--) if (values[index] < values[index - 1]) { swap(index, index - 1); sorted = false; } return sorted; } static void shortBubble() // Sorts the values array using the bubble sort algorithm. // The process stops as soon as values is sorted. { int current = 0; boolean sorted = false; while ((current < (SIZE - 1)) && !sorted) { sorted = bubbleUp2(current, SIZE - 1); current++; } } ///////////////////////////////////////////////////////////////// // // Insertion Sort static void insertItem(int startIndex, int endIndex) // Upon completion, values[0]..values[endIndex] are sorted. { boolean finished = false; int current = endIndex; boolean moreToSearch = true; while (moreToSearch && !finished) { if (values[current] < values[current - 1]) { swap(current, current - 1); current--; moreToSearch = (current != startIndex); } else finished = true; } } static void insertionSort() // Sorts the values array using the insertion sort algorithm. { for (int count = 1; count < SIZE; count++) insertItem(0, count); } ///////////////////////////////////////////////////////////////// // // Merge Sort static void merge (int leftFirst, int leftLast, int rightFirst, int rightLast) // Preconditions: values[leftFirst]..values[leftLast] are sorted. // values[rightFirst]..values[rightLast] are sorted. // // Sorts values[leftFirst]..values[rightLast] by merging the two subarrays. { int[] tempArray = new int [SIZE]; int index = leftFirst; int saveFirst = leftFirst; // to remember where to copy back while ((leftFirst <= leftLast) && (rightFirst <= rightLast)) { if (values[leftFirst] < values[rightFirst]) { tempArray[index] = values[leftFirst]; leftFirst++; } else { tempArray[index] = values[rightFirst]; rightFirst++; } index++; } while (leftFirst <= leftLast) // Copy remaining items from left half. { tempArray[index] = values[leftFirst]; leftFirst++; index++; } while (rightFirst <= rightLast) // Copy remaining items from right half. { tempArray[index] = values[rightFirst]; rightFirst++; index++; } for (index = saveFirst; index <= rightLast; index++) values[index] = tempArray[index]; } static void mergeSort(int first, int last) // Sorts the values array using the merge sort algorithm. { if (first < last) { int middle = (first + last) / 2; mergeSort(first, middle); mergeSort(middle + 1, last); merge(first, middle, middle + 1, last); } } ///////////////////////////////////////////////////////////////// // // Quick Sort static int split(int first, int last) { int splitVal = values[first]; int saveF = first; boolean onCorrectSide; first++; do { onCorrectSide = true; while (onCorrectSide) // move first toward last if (values[first] > splitVal) onCorrectSide = false; else { first++; onCorrectSide = (first <= last); } onCorrectSide = (first <= last); while (onCorrectSide) // move last toward first if (values[last] <= splitVal) onCorrectSide = false; else { last--; onCorrectSide = (first <= last); } if (first < last) { swap(first, last); first++; last--; } } while (first <= last); swap(saveF, last); return last; } static void quickSort(int first, int last) { if (first < last) { int splitPoint; splitPoint = split(first, last); // values[first]..values[splitPoint - 1] <= splitVal // values[splitPoint] = splitVal // values[splitPoint+1]..values[last] > splitVal quickSort(first, splitPoint - 1); quickSort(splitPoint + 1, last); } } ///////////////////////////////////////////////////////////////// // // Heap Sort static int newHole(int hole, int lastIndex, int item) // If either child of hole is larger than item this returns the index // of the larger child; otherwise it returns the index of hole. { int left = (hole * 2) + 1; int right = (hole * 2) + 2; if (left > lastIndex) // hole has no children return hole; else if (left == lastIndex) // hole has left child only if (item < values[left]) // item < left child return left; else // item >= left child return hole; else // hole has two children if (values[left] < values[right]) // left child < right child if (values[right] <= item) // right child <= item return hole; else // item < right child return right; else // left child >= right child if (values[left] <= item) // left child <= item return hole; else // item < left child return left; } static void reheapDown(int item, int root, int lastIndex) // Precondition: Current root position is "empty". // // Inserts item into the tree and ensures shape and order properties. { int hole = root; // current index of hole int newhole; // index where hole should move to newhole = newHole(hole, lastIndex, item); // find next hole while (newhole != hole) { values[hole] = values[newhole]; // move value up hole = newhole; // move hole down newhole = newHole(hole, lastIndex, item); // find next hole } values[hole] = item; // fill in the final hole } static void heapSort() // Sorts the values array using the heap sort algorithm. { int index; // Convert the array of values into a heap. for (index = SIZE/2 - 1; index >= 0; index--) reheapDown(values[index], index, SIZE - 1); // Sort the array. for (index = SIZE - 1; index >=1; index--) { swap(0, index); reheapDown(values[0], 0, index - 1); } } ///////////////////////////////////////////////////////////////// // // Main public static void main(String[] args) { initValues(); printValues(); System.out.println("values is sorted: " + isSorted()); System.out.println(); // make call to sorting method here (just remove //) // selectionSort(); // bubbleSort(); // shortBubble(); // insertionSort(); // mergeSort(0, SIZE - 1); // quickSort(0, SIZE - 1); // heapSort(); printValues(); System.out.println("values is sorted: " + isSorted()); System.out.println(); } } 

Run your code to sort data with different data set size.

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Database Design Query Formulation And Administration Using Oracle And PostgreSQL

Authors: Michael Mannino

8th Edition

1948426951, 978-1948426954

More Books

Students also viewed these Databases questions

Question

What are Measures in OLAP Cubes?

Answered: 1 week ago

Question

How do OLAP Databases provide for Drilling Down into data?

Answered: 1 week ago

Question

How are OLAP Cubes different from Production Relational Databases?

Answered: 1 week ago