This is a lab and I need help with the last image that I uploaded here. I have done everything before the lab (assuming that it is correct)... scroll down to see what I need help with. I have provided the entire lab so you can understand what the lab is. Let me know if you have any questions.

Refraction Simulation Objective: The following objectives will be investigated during this activity: 1. To identify.r an unknown substance based upon its index of refraction. 2. To determine the critical angle of a set of materials. 3. To identify.r the criteria needed to get total internal reection {TIR}. Simulation: lClick the link below to go to the simulation. htt stifmwr. h sicsclassroomcothh sics-Interactiveszefraction-andLensesa'Refractione'Refraction-lnteractiv Once in the simulation, play,r around with the controls to get acquainted with the simulation. You can move the laser [black box) around the simulatsaddcf ion. You can add a protractor to get angles of incidence and refraction. You can change the materials that make up the top and bottom layers. button at the top of the simulation. Click GO and let the laser do its thing. Then move the center of the protractor to the point where the three rays (incident, reflected, and refracted) intersect. See image below. go clear reset hide protractor Top Substance Bottom Substance air water 01! vacuum air water 1=1.0 1=1.MJ 7 =1.33 1=1.47 n=10 n=1.0103 -1.13 n=1.47 n=2.42 #1 #2 n=? n=247 #2 n=? For this simulation TURN OFF the Reflected Angle. To do this, click on the Blue Button in the upper right corner that says Hide Partial Reflection. We will not be looking at this, but know that some light does get reflected off a boundary between two substances. This is why you can partially see your reflection in a glass window. Although the reflection is faint, some of the light does bounce off the glass, while most of it is transmitted through. You will be using Snell's Law to determine the index of refraction of an unknown material. You will use the equation below to determine the index of refraction in Part 1: n sin 0 = n, sin 0, n, = index of refraction for substance #1 n, = index of refraction for substance #2 0, = angle of incidence 6, = angle of refractionPart 1: Determining the identity of an unknown substance from its index of refraction Directions: ***Make sure your calculator is in DEGREE mode!* * 1. Set the top boundary to air and the bottom boundary to Unknown 1. 2. Move the laser so that the incident ray matches that in Table 1 below. Do your best to be as accurate as possible. This will produce the best results. 3. Record the angle of refraction. 4. Calculate the index of refraction for the unknown for each incident angle. Show one calculation in the space below the table. Report your index of refraction values to 3 decimal places. 5. Determine the average index of refraction. 6. Identify the unknown material. Table 1: Air into unknown #1 Incident Angle Refracted Angle Index of refraction Average Index of Identity of ('0) (@2) refraction unknown #1 10 5.5 1.816 20 10 1.972 30 14.5 2.001 40 18 2.080 1.99 Cubic Zirconia 50 22.5 2.004 60 25.5 2.015 70 27.5 2.041Part 2: Determining the identity of an unknown substance from its index of refraction Directions: **Make sure your calculator is in DEGREE mode!** 7. Set the top boundary to air and the bottom boundary to Unknown 2. 8. Move the laser so that the incident ray matches that in Table 1 below. Do your best to be as accurate as possible. This will produce the best results. 9. Record the angle of refraction. 10. Calculate the index of refraction for the unknown for each incident angle. Show one calculation in the space below the table. Report your index of refraction values to 3 decimal places. 11. Determine the average index of refraction. 12. Identify the unknown material. Table 2: Air into unknown #2 Incident Angle Refracted Angle Index of refraction Average Index of Identity of (01) (@2) refraction unknown #2 10 5 1.998 20 10 1.975 30 15 1.937 40 20 1.885 1.775 Ruby 50 25.5 1.780 60 28.5 1.820 70 31.5 1.804Table 4: Determining the critical angle Incident Medium Refractive Medium Critical angle (") (Top Layer) (Bottom Layer) Water (n = 1.33) Air (n = 1.00) Oil (n = 1.47) Air (n = 1.00) Diamond (n = 2.42) Air (n = 1.00) Water (n = 1.33) Oil (n = 1.47) Oil (n = 1.47) Water (n = 1.33) Diamond (n = 2.42) Water (n = 1.33) Diamond (n = 2.42) Oil (n = 1.47) Oil (n = 1.47) Diamond (n = 2.42) Analysis: 1. Not all of the pairs in Table 4 produced total internal reflection. Which pairs did not have TIR? 2. What did the pairs that did not produce TIR in Table 3 have in common? You should have two answers for this.Table 6 + Possible Unknown Index of Refraction Materials Water 1.33 Acetone 1.36 Vinegar 1.37 Vegetable oil 1.47 Gelatin 1.24 Crown Glass 1.52-1.62 Alcohol 1.36 Ruby 1.71 Sugar solution (70%) 1.40 Cubic Zirconia 2.15 4. Comparing your two unknowns and air, put them in order of increasing inde