This is a MatLab Question, I have tried several versions of answers, but none could pass the test. Please help!

Version 1:

stringMetaOne = not(inputString==' '); stringMetaTwo = isletter(inputString); metaString = and(stringMetaOne,stringMetaTwo); [indicator,startPositionOfAllOnes,endPositionOfAllOnes,lengthofAllOnes]=FindConsecutiveOnes(metaString); for i = 1:length(startPositionOfAllOnes) word = inputString(startPositionOfAllOnes(i):endPositionOfAllOnes(i)); revWord = ReverseLetters(word); inputString(startPositionOfAllOnes(i):endPositionOfAllOnes(i))=revWord; end outputString=inputString; end

function sout = ReverseLetters(sin) sout = ''; if length(sin) == 1 sout(end + 1) = sin(1); else sout(end+1) = sin(1); for i = 1:length(sin)-2 if i % 2 == 0 sout(end + 1)= sin(length(sin) - i); else sout(end + 1) = sin(i); end end sout(end+1) = sin(end); end end

function [indicator,startPositionOfAllOnes,endPositionOfAllOnes,lengthofAllOnes] = FindConsecutiveOnes(inputArray) indicator = zeros(1, length(inputArray)); startPositionOfAllOnes=[]; endPositionOfAllOnes=[]; lengthofAllOnes =[]; j = 1; for i = 1 : length(inputArray) if i == 1 && inputArray(i) == 1 startPositionOfAllOnes(j) = i; elseif inputArray(i) == 1 && inputArray(i-1) == 0 startPositionOfAllOnes(j) = i; elseif i ~= 1 && inputArray(i) == 0 && inputArray(i-1) == 1 endPositionOfAllOnes(j) = i-1; lengthofAllOnes(j) = endPositionOfAllOnes(j)-startPositionOfAllOnes(j) + 1; j = j + 1; end end if inputArray(length(inputArray)) == 1

endPositionOfAllOnes(j) = length(inputArray);

lengthofAllOnes (j) = endPositionOfAllOnes(j) - startPositionOfAllOnes(j) + 1; end

for j = 1 : length(lengthofAllOnes)

indicator(startPositionOfAllOnes(j)) = lengthofAllOnes (j); end end

Version 2:

function [outputString] = ScrambleLetters(inputString)

onestring = not(inputString==' ');

twostring = isletter(inputString);

mstring = and(onestring,twostring);

[indicator,start_position,end_position,length_ones]=FindConsecutiveOnes(mstring);

%Iterate value

for i = 1:length(start_position)

word11 = inputString(start_position(i):end_position(i));

%Reverse the word11.

revword11 = ReverseLetters(word11);

inputString(start_position(i):end_position(i))=revword11;

%end loop.

end

%result

outputString=inputString;

end

%ReverseLetters function.m

function soutput = ReverseLetters(sin)

soutput = '';

if length(sin) == 1

soutput(end + 1) = sin(1);

else

soutput(end+1) = sin(1);

%Iterate value

for i = 1:length(sin)-2

if i % 2 == 0

soutput(end + 1)= sin(length(sin) - i);

else

soutput(end + 1) = sin(i);

end

end

soutput(end+1) = sin(end);

end

end

%consecutive numbers function.m

function [indicator,start_position,end_position,length_ones] = FindConsecutiveOnes(in_array)

indicator = zeros(1, length(in_array));

start_position=[];

end_position=[];

length_ones =[];

j = 1;

for i = 1 : length(in_array)

if i == 1 && in_array(i) == 1

start_position(j) = i;

elseif in_array(i) == 1 && in_array(i-1) == 0

start_position(j) = i;

elseif i ~= 1 && in_array(i) == 0 && in_array(i-1) == 1

end_position(j) = i-1;

length_ones(j) = end_position(j)-start_position(j) + 1;

j = j + 1;

end

end

if in_array(length(in_array)) == 1

end_position(j) = length(in_array);

length_ones (j) = end_position(j) - start_position(j) + 1;

end

for j = 1 : length(length_ones)

indicator(start_position(j)) = length_ones (j);

%Terminate the for loop.

end

end

Version 3:

function [outputString] = ScrambleLetters(inputString)

%Define two string variables

%Check for whitespace and letter.

stringMetaOne = not(inputString==' ');

stringMetaTwo = isletter(inputString);

%Meta String contains letter.

metaString = and(stringMetaOne,stringMetaTwo);

%Extract the results from FindConsecutiveOnes() function

[indicate,startPositionOfOnes,endPositionOfOnes,lengthofOnes]=FindConsecutiveOnes(metaString);

%Iterate through the string for the words.

for i = 1:length(startPositionOfOnes)

%Extract the word.

word = inputString(startPositionOfOnes(i):endPositionOfOnes(i));

%Reverse the word.

revWord = ReverseLetters(word) ;

%Reform the input string.

inputString(startPositionOfOnes(i):endPositionOfOnes(i))=revWord;

%Terminate the loop.

end

%Set the function result.

outputString=inputString;

%Terminate the function.

end

%Define the function to reverse the letters.

function sout = ReverseLetters(sin)

%Define a variable.

sout = '';

%Check for the string length.

if length(sin) == 1

sout(end + 1) = sin(1);

%Reverse the string.

else

%Store last value in the variable sout.

sout(end+1) = sin(1);

%Iterate through the length of the string.

for i = 1:length(sin)-2

%Check for even positions.

if i % 2 == 0

%Set the string.

sout(end + 1)= sin(length(sin) - i);

else

sout(end + 1) = sin(i);

%Terminate the inner if else.

end

%Terminate the loop.

end

sout(end+1) = sin(end);

%Terminate the outer if else.

end

%Terminate the function.

end

%Define the function to set the consecutive numbers.

function [indicate,startPositionOfOnes,endPositionOfOnes,lengthofOnes] = FindConsecutiveOnes(inputArray)

%Set the value of the function parameter.

indicate = zeros(1, length(inputArray));

startPositionOfOnes=[];

endPositionOfOnes=[];

lengthofOnes=[];

%Set the position.

j = 1;

%Iterate through the array.

for i = 1 : length(inputArray)

%Check the first charcter and position of the array.

if i == 1 && inputArray(i) == 1

%Set the start.

startPositionOfOnes(j) = i;

elseif inputArray(i) == 1 && inputArray(i-1) == 0

startPositionOfOnes(j) = i;

%Check for the last position and set the end.

elseif i ~= 1 && inputArray(i) == 0 && inputArray(i-1) == 1

endPositionOfOnes(j) = i-1;

%Set the length.

lengthofOnes(j) = endPositionOfOnes(j)-startPositionOfOnes(j) + 1;

%Set the position.

j = j + 1;

%Terminate the if elseif.

end

%Terminate the for loop.

end

%Check the array length and set the start and end position.

if inputArray(length(inputArray)) == 1

endPositionOfOnes(j) = length(inputArray);

lengthofOnes(j) = endPositionOfOnes(j) - startPositionOfOnes(j) + 1;

%Terminate the if else.

end

%Iterate through the length of the ones.

%Set the indicator as per the ons position.

for j = 1 : length(lengthofOnes)

indicate(startPositionOfOnes(j)) = lengthofOnes(j);

%Terminate the for loop.

end

%Terminate the function.

end

It dseon't mettar waht oedrr the Irettes in a wrod are Write a function ScrambleLetters to take a phrase consisting of words and non-letters, identify all the words (contain only letters) and then for all words reverse the subsequence of the letters leaving the first and the last letter of the word unchanged. The input phrase could be any length. The input sentence and output phrase should be a string scalar. For example: >>inputString "Ones and 1 is sometimes two"; >>[outputString] = ScrambleLetters (inputString) outputString- "Oens and 1 is semitemos two" Your Function Save C Reset MATLAB Documentation function [outputString] = ScrambleLetters ( inputString) 3 % Your new code goes here