this is for stat please answer clearly

Assume that a procedure yields a binomial distribution with n = 8 trials and a probability of success of p = 0.20. Use a binomial probability table to find the probability that the number of successes x is exactly 6. 5 Click on the icon to View the binomial probabilities table. (E P(6) = D (Round to three decimal places as needed.) Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. @ Click the icon to View the data table. The mean is p = D girl(s). (Round to one decimal place as needed.) The standard deviation is o = D girl(s). (Round to one decimal place as needed) Table of numbers of girls and probabilities Number of Girls x P(x) 0.004 0.028 0.117 0.214 ONOUIAWN- O 0.288 0.211 0.107 0.026 0.005Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 31 couples. Complete parts (a) through (0) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 31 births. The value of the mean is u = (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.Values of girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Round to one decimal place as needed.) c. Is the result of 28 girls a result that is significantly high? What does it suggest about the effectiveness of the method? The result significantly high, because 28 girls is girls. A result of 28 girls would suggest that the method (Round to one decimal place as needed.)Binomial Probabilities 01 .05 .10 .20 .30 40 .50 60 .70 80 .90 95 99 950 .902 .810 .640 .490 360 .250 160 080 040 010 002 0+ 020 .095 .180 .320 .420 .480 .500 480 420 320 .180 .095 .020 0+ 002 .010 .040 .090 .160 .250 360 490 .640 810 .902 980 3 .970 .857 .729 .512 .343 .216 .125 054 027 .005 .001 0+ 0+ .135 .243 .384 .441 432 .375 288 .189 .095 027 007 0+ 029 0+ .007 .027 .096 .189 .288 .375 432 441 354 243 .135 .029 UN-OWN-ONO 0+ 0+ .001 .008 .027 .064 .125 216 343 .512 .729 857 .970 .951 .815 .656 410 .240 .130 .062 026 003 .002 0+ 0+ 0+ 039 171 .292 410 .412 .346 .250 .154 .076 .026 034 0+ 0+ .001 .014 .049 .154 .265 .346 .375 346 265 .154 049 .014 001 0+ 0+ .004 .026 .076 .154 .250 346 412 410 292 171 .039 0+ 0+ 0+ .002 .008 026 .062 .130 240 410 .656 815 .961 0+ 5 .951 .774 .590 .328 .168 .078 .031 010 002 0+ 0+ 0+ 048 .204 .328 .410 .360 .259 .156 077 028 .005 0+ 0+ 0+ UN - O 021 .073 .205 .309 .346 .312 230 .132 .051 .005 001 0+ 001 0+ .001 008 .051 .132 .230 .312 346 309 205 073 021 001 0+ 0+ 0+ 006 .cea 077 .156 259 350 410 328 204 048 0+ 0+ 0+ 0+ .010 .031 078 .168 328 590 .774 .951 6 0 .941 .735 .531 .262 .118 .047 .016 004 .001 0+ 0+ 0+ 0+