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THIS IS FOR STAT PLEASE ANSWER CLEARLY Q1 Fill in the blank. The distribution is a discrete probability distribution that applies to the number of
THIS IS FOR STAT PLEASE ANSWER CLEARLY
Q1
Fill in the blank. The distribution is a discrete probability distribution that applies to the number of occurrences of some event over a specied interval. (E _ The |:| distribution is a discrete probability distribution that applies to the number of occurrences of some event over a specified interval. In a recent year, an author wrote 186 checks. Use the Poisson distribution to find the probability that, on a randomly selected day, he wrote at least one check. The probability is D. (Round to three decimal places as needed.) A normal distribution is informally described as a probability distribution that is "bellshaped" when graphed. Draw a rough sketch of a curve having the bell shape that is characteristic of a normal distribution. Choose the correct answer below. A. B. C. D. LAAM Assume the readings on thermometers are normally distributed with a mean of 0 C and a standard deviation of 1.00 C. Find the probability that a randomly selected thermometer reads between - 2.18 and - 1.64 and draw a sketch of the region. Click to view page 1 of the table. Click to view page 2 of the table. . . . Sketch the region. Choose the correct graph below. O A. O B. O c. + + -2.18 -1.64 -2.18 -1.64 -2.18 -1.64 The probability is (Round to four decimal places as needed.)Standard Normal Table (Page 1) NEGATIVE 2 Scores Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 \"3.50 and lower .0001 3 4 .0003 0003 0003 0003 0003 .0003 0003 .0003 0003 .0002 \"3.3 .0005 .0005 .0005 .0004 .0004 .0004 0004 .0004 .0004 .0003 3 2 .0002 000! 0006 0006 0006 .0006 0006 .0005 .0005 .0005 \"3.1 .0010 .0005 0009 .0009 .0008 .0008 0008 .0008 .0007 .0007 3 0 .0 013 0013 0013 001? 0 01? .0011 0011 .0011 0010 .0010 \"2.9 .0019 .0018 .0018 .0017 .0016 .0016 0015 .0015 .0014 .0014 ?.8 .0026 .0095 .0024 .0023 .0023 .0021? 0021 .0021 .0020 .0019 \"2.7 .0035 .0034 .0033 .0032 .0031 .0030 0029 .0028 .0027 .0026 2 6 .004! 0045 004.4 004.3 0041 .0040 0059 .0038 003} .0036 \"-2.5 .0062 .0060 .0059 .0057 .0055 .0054 0052 .0051 "' .0049 .0048 2.4 .0082 .O 030 .0078 .00 75 .0 073 .0071 0069 .0068 .0066 .0064 \"~23 .0107 .0104 .0102 .0099 .0096 .0094 0091 .0089 .0087 .0084 2.? .0139 .0136 .0132 .01?9 .0125 .012? 0119 .0116 .0113 .0110 "-2.1 .0179 .0174 .0170 .0166 .0162 .0158 0154 .0150 .014 6 .0143 Standard Normal Table (Page 2) POSITIVE 2 Scores Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 5040 5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.2 5793 .5832 5871 5910 5948 5987 .6026 6064 .6105 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 6480 .6517 0.4 6554 6591 .6628 6664 .6700 .6736 .6772 .6808 6844 .6879 0.5 .6915 6950 .6985 .7019 .7054 .7088 .7123 7157 .7190 .7224 0.6 7757 7791 7324 7357 7389 74?? .7454 7486 .7517 .7549 0.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 7823 .7852 0.8 78-81 7910 79-59 7967 .7995 8023 .8051 80/8 .8106 .8155 0.9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 1.0 .9413 843 B 8461 .8485 .8508 .8531 .8 554 .8577 .8599 .8621 1.1 .8643 8665 8686 .8708 .8729 .8749 .87 70 .8790 .8810 .8830 1.? 8849 8869 8888 890 7 .8975 .8944 .896? .8980 .8997 9015 1.3 .9032 .9049 .9066 .9082 .9099 .9115 .9131 .9147 .9162 .9177 1.4 .9192 9207 9222 .9236 .9251 .9265 .9279 9292 9306 .9319 1.5 .9332 .9345 .9357 .9370 .9382 .9394 .9406 .9418 .9429 .9441 1.6 9452 9463 9474 9484 .9495 " .9505 .9515 9525 .9555 .9545 Find the indicated area under the curve of the standard normal distribution; then convert it to a percentage and fill in the blank. About \"/0 of the area is between 2 = - 1 and z = 1 (or within 1 standard deviation of the mean). (E About |:|% of the area is between 2 = 1 and 2 =1 (or within 1 standard deviation of the mean). (Round to two decimal places as needed.) Find the indicated 2 score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. 0.1736 (E The indicated 2 score is D. (Round to two decimal places as needed.) Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 86 (E The area of the shaded region is D. (Round to four decimal places as needed.) Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per minute. Answer the following questions. (E What are the values of the mean and standard deviation after converting all pulse rates of (x - l1) 0' women to z scores using 2 = '? FD FD The original pulse rates are measure with units of "beats per minute". What are the units of the corresponding 2 scores? Choose the correct choice below. The z scores are measured with units of "minutes per beat." {I} A. {I} B. The z scores are measured with units of "beats." {I} C. The z scores are measured with units of "beats per minute." {I} D. The z scores are numbers without units of measurement. Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to View [193 1 of the table. Click to View [age 2 of the table. 0 6 The indicated IQ score, x, is D. (Round to one decimal place as needed.) Standard Normal Table (Page 2) POSITIVE 2 Scores Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 5040 5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.2 5 793 .5832 5871 5910 .5948 598 7 .6026 6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 6480 .6517 0.4 6554 6591 .6628 6654 6700 6736 .6772 .6808 6844 6879 0.5 .6915 6950 .6985 .7019 .7054 .7088 .7123 7157 .7190 .7224 0.6 7257 7291 7324 7357 .7389 74?? . 7454 7486 .7517 .7549 0.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 7823 .7852 0.8 78-81 7910 793 9 7967 .7995 8023 .8051 80 78 .8106 .8133 0.9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 1.0 .8413 3438 8461 .8485 .8508 .8531 .8554 .8577 .8599 .8521 1.1 .8643 8665 8686 .8708 .8729 .8749 .8770 .8 790 .8810 .8830 1.2 8849 8869 8888 890 7 .8925 8944 .8962 .8980 .8997 .9015 1.3 .9032 .9049 .9066 .9082 .9099 .9115 .9131 .9147 .9162 .9177 1.4 .9192 9207 9222 .9236 .9251 .9265 .9279 9292 9306 .9319 1.5 .9332 .9345 .9357 .9370 .9382 .9394 .9406 .9418 .9429 .9441 1.6 9452 9463 94/4 9484 .9495 " 9505 .9515 9525 .9535 .9545 \fIn a recent year (365 days), there were 671 murders in a city. Find the mean number of murders per day, then use that result to find the probability that in a single day, there are no murders. Would 0 murders in a single day be a significantly low number of murders? . . . The mean number of murders per day is (Round to one decimal place as needed.) The probability that in a single day, there are no murders is (Round to three decimal places as needed.) Would 0 murders in a single day be a significantly low number of murders? Yes, because the probability is 0.05 or less.. O Yes, because the probability is greater than 0.05. O No, because the probability is greater than 0.05. O No, because the probability is 0.05 or less.Standard Normal Table (Page 1) NEGATIVE 2 Scores '4 (1 Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .0 B .09 -3.50 and lower .0001 3 4 .0003 0003 0003 0003 .0 003 .0003 0003 .0003 0003 .0002 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0004 .0004 .0004 .0003 .'1 2 .0007 000;" 0006 0006 0006 .0006 0006 ,0005 .0005 .0005 ~31 .0010 .0009 .0009 .0009 .0008 .0008 0003 .0008 .0007 .0007 5 0 .0013 0015 0013 001? 0017 .0011 0011 .0011 0010 .0010 -2.9 .0019 .0018 .0018 .0017 .0016 .0016 .0015 .0015 .0014 .0014 2.8 .0026 .0095 .0024 00?} .0 023 .002? 0021 .0091 .0020 .0019 -2.7 .0035 .0034 .0033 .0032 .0031 .0030 .0029 .0025 .0027 .0026 2 6 .004! 0045 0044 004.5 0041 .0040 00.59 .0038 00.5\"I .0056 -2.5 .0062 .0060 .0059 .0057 .0055 .0054 .0052 .0051 "' .0049 .0043 2.4 .0082 .0080 .0078 .0075 .0 073 .0071 0069 .0068 .0066 .0 064 '23 .0107 .0104 .0102 .0099 .0096 .0094 .0091 .0089 .0087 .0084 ?.2 .0139 .0136 .0137 .0129 .0125 .0127 0119 .0116 .0113 .0110 -2.1 .0179 .0174 .0170 .0166 .0162 .0158 .0154 .0150 .0146 .0143Step by Step Solution
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