This is how to calculate the number of required kanbans in the machine shop

$2$:$2$~$=\frac{900\frac{12}{60}(1+0\mathrm{.}1)}{150}$

As each container holds $150$ units, what is the maximum authorized inventory in the machine shop $2?$

$500$

$300$

$800$

$200$

Submit

Machine Shop $2$

Information for Machine Shop $2$

$\backslash$table$[[\backslash$table$[[$Demand $($from distribution centers$)$ units$],[$per hour$]],\backslash$table$[[$Machine$],[$Shop $2]]],[\backslash$table$[[$Average lead time for replenishment of$],[$one container $($minutes$)]],12],[$Safety factor,$0\mathrm{.}10],[$Container size,$150]]$

where

$N=$ Total number of kanbans $($one kanban per container$)$

$D=$ Average usage rate of using work centre

$T=$ Average lead time for replenishment of one container $($includes wait before