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This problem consists of two parts. In Part A there is an homogeneous reaction within the fluid. The reaction creates species at a constant rate

This problem consists of two parts. In Part A there is an homogeneous reaction within the fluid. The
reaction creates species at a constant rate Ri, moles im3s. The walls catalytically destroy species i
infinitely rapidly.
In Part B there is no homogeneous reaction, but there is a surface reaction at the inside walls s creating
species i at a constant rate of Ri(surface) moles im2s. Specie i then diffuses into the fluid. For both Parts
A and B assume (pseudo ) binary diffusion because species i is very dilute.
PART A (40 POINTS)
A reacting incompressible fluid flows between two parallel flat plates. The bottom plate moves with velocity V. The
top plate is stationary. A developing concentration profile of, say species i is formed within the fluid by a constant
volumetric reaction rate Ri moles ?m3s. At x=0 the volumetric reaction source is turned on. For x0 there is NO
reaction. The walls destroy the species i extremely rapidly. A concentration profile, Ci(x,y) develops, due to the
volumetric reaction source. There is no imposed pressure drop - motion is caused by the bottom sliding plate.. The
concentration at x=0 is C0. Assume there is a steady state, unless you conclude there is not. Then explain. Assume
pseudo-binary diffusion, constant total molar concentration, incompressible fluid etc.
Steadv linear velocitv profile
Walls destroy species i infinitely rapidly
I. Prove that the steady velocity profile is given by vx=V(1-yH)
II. Write down the species balance equation with the appropriate boundary conditions.
Scale appropriate variables, non-dimensionalize, and derive an expression for the characteristic
concentration difference, and the characteristic length in the x-direction. Interpret this length physically.
(25)
III. Assume the Peclet (Mass) Number, Pem=ReSc=VHD1, and use this to simplify the equation above
by eliminating one of the diffusion terms. Provide a physical explanation as to what this means. (10)
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