This P-value (and test statistic) leads to a decision to... O reject the null O accept the null O fail to reject the null O reject the alternative As such, the final conclusion is that... O The sample data support the assertion that there is a different proportion of only children in the G&T program. Q There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program. In a certain school district, it was observed that 28% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 98 out of 281 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.01 level of significance. What is the hypothesized population proportion for this test? p = (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? Oone-tailed test O two-tailed test Choose the correct pair of hypotheses for this situation: (A) (B) (C) Ho:p = 0.28 Ho:p = 0.28 Ho: p = 0.28 Ha : p 0.28 (D) (E) (F) Ho:p = 0.349 Ho:p = 0.349 Ho: p = 0.349 Ha: p 0.349 (A) (B) (C) (D) (E ) ( F ) oooo0 Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic (z-score) for this sample based on the sample proportion? Z = (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places. )