This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise The frequency of vibrations of a piano string varies directly as the square root of the tension on the string and inversely as the length of the string. The middle A string has a frequency of 440 vibrations per second. Find the frequency of a string that has 1.23 times as much tension and is 1.8 times as long. Step 1 Let f be the frequency (in vibrations per second), 7 be the tension, and / be the length of the piano string. Because f varies directly as the square root of 7 and inversely as /, we get the following. Of = K K Of = IT Of = KVT Of = KVT