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This question is a assignment of Linear Algebra, especially about Singular value decomposition. Professor said AA T 's eigenvectors are column vectors of U matrix,
This question is a assignment of Linear Algebra, especially about "Singular value decomposition". Professor said "AAT's eigenvectors are column vectors of U matrix", but I'm not sure that should I use this. sigma is an r x r diagonal matrix whose diagonal entries are the nonzero singular values. V is a matrix that's column vectors are eigenvector of A. Following picture is about U matrix.
If we define 1 = Av; j = 1,..., 1 oj and U. =[u u, ] 1 For a 4x3 matrix A with columns (1,0,0,1), (0,1,0,0), and (1,0,1,-1), (a) Eigenvalues of ATA are 3, 2, 1 and their corresponding eigenvectors are (0,0,1), (1,0,0), and (0,1,0), respectively. Find an orthonormal basis of AAT, which may form the matrix U such that A = UEVT. If we define 1 = Av; j = 1,..., 1 oj and U. =[u u, ] 1 For a 4x3 matrix A with columns (1,0,0,1), (0,1,0,0), and (1,0,1,-1), (a) Eigenvalues of ATA are 3, 2, 1 and their corresponding eigenvectors are (0,0,1), (1,0,0), and (0,1,0), respectively. Find an orthonormal basis of AAT, which may form the matrix U such that A = UEVTStep by Step Solution
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