Three perfect polarizers are placed in sequence and receive incoming light from one side as shown in the figure below. The first polarizer has its optic axis oriented vertically. The second is oriented 0 = 20.6 degrees to one side of vertical. The third is oriented horizontally. Polarized Light Intensity = 13 Polarized Light Intensity = 12 Polarized Light Intensity = /1 Unpolarized Light Intensity = lo What fraction of the incoming intensity gets through the first polarizer? I1/Io = What fraction of the incoming intensity gets through both the first and second polarizers? I2/Io = What fraction of the incoming intensity gets through the first, second, and third polarizers? I3/Io = How much intensity would get through if the second and third polarizers were exchanged? I3/Io =how. 9 = 20 . 6 Here wecan apply malus's law to Find the Interpity transmitted through the polarizerss . when an unpolarized light passer through a polarizer, its intensity reduced to half. Then the fraction of incoming intensity gets through the first polarizer The intensity of light falls on the second polarizex is In = o.ST. Applying the malus's law For the second polarizer, d 0.SI. (Cop 20.6 )12 I2 - 0.438 Foord A IO The intensity of light falls on the third polarizer Iz = 0. 438 16 Applying the malus's law F3 = I2 ( (ODO ) 2 9 = 90 - 20.6 - 69. 4 F3 = 0. 43 850( $ 69. 4 Is - F0.0542 Tosecond polarize is removed of the Then the angle between the tranmiston axis of first and last in O= go That is internity passed through the polarizer is .sixDog Dow To What Fraction of the incoming, internity getts through the first polarizer ? In/ 5. = 0-5 What Fraction of the incoming intensity gett through both the first and second Polarizers ? Iz To = 0.438 What fraction of the incoming intensity gets through the first, second and third polarizery ? I3 / Io = 60-0542 How much intensity would get through of the second and third polarizers wore exchanged? I'llTo = 0