Three portions of the same liquid are mixed in a container that prevents the exchange of heat with the environment. Portion A has a mass m and a temperature of 96.0 C, portion B also has a mass m but a temperature of 83.0 C, and portion C has a mass me and a temperature of 44.0 C. What must be the mass of portion C so that the final temperature T, of the three-portion mixture is T, = 51.0 "C? Express your answer in terms of m: for example, me = 2.20 m.