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Titanium(IV) chloride decomposes to form titanium and chlorine, like this: TiCl (0) - Ti(s)+2 C12(9) At a certain temperature, a chemist finds that a 3.8
Titanium(IV) chloride decomposes to form titanium and chlorine, like this: TiCl (0) - Ti(s)+2 C12(9) At a certain temperature, a chemist finds that a 3.8 L reaction vessel containing a mixture of titanium(IV) chloride, titanium, and chlorine at equilibrium has the following composition: compound amount Tici, 4.97 g Ti 1.75 g Cl2 2.52 g Calculate the value of the equilibrium constant K, for this reaction. Round your answer to 2 significant digits. K = 0 $
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