To budget for the coming year, a community hospital must estimate the proportion of treated patients who will not be able to make payment in full. In a random sample of 568 patients treated in the previous year, 181 failed to make payment in full. What is an 90% confidence interval for the proportion of patients who will not make full payment to the hospital? a) (0.125, 0.162) Ob) (0.137, 0.160) c) (0.139, 0.157) d) (0.287, 0.351) Previous Page Next Page Page 11 of 11 To budget for the coming year, a community hospital must estimate the proportion of treated patients who will not be able to make payment in full. In a random sample of 568 patients treated in the previous year, 181 failed to make payment in full. What is an 90% confidence interval for the proportion of patients who will not make full payment to the hospital? a) (0.125, 0.162) Ob) (0.137, 0.160) c) (0.139, 0.157) d) (0.287, 0.351) Previous Page Next Page Page 11 of 11