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To determine the heat of the neutralization reaction of HCI and NaOH, 20.00 mL of 1.50 M HCl(aq) and 20.00 mL of 1.50 M NaOH(aq),

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To determine the heat of the neutralization reaction of HCI and NaOH, 20.00 mL of 1.50 M HCl(aq) and 20.00 mL of 1.50 M NaOH(aq), both initially at 18 C are added to a Styrofoam- cup calorimeter and allowed to react. The temperature rises to 28 C. Determine the heat of the neutralization reaction. (Assume that no heat is lost to the surrounding air)(Specific heat of water is 4.18 Jgc!)(Density of NaCl (aq)= 1 g/mL). Q=mcat A)-836K B)-625 kJ C) 715 kJ D) 418 kJ

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