To draw line segment #1, we must consider the inequality (-1A + 2B <= 8) as an equation (-1A + 2B = 8) and find two points that satisfy this equation. When A = 0, then B = 4, so one point is (0, 4). When A = 4, B = 6, so another point is (4, 6). To draw line #1, we need the points (0, 4) and (4, 6). The feasible region is determined by testing a point such as the origin (0, 0), which satisfies the inequality as 0 + 0 <= 8, showing that the feasible region is the right-below area of line #1. To draw line segment #2, we need to consider the inequality (1A + 2B <= 12) as an equation (1A + 2B = 12) and find two points. When A = 0, then B = 6, so one point is (0, 6). When B = 0, A = 12, so another point is (12, 0). To draw line #2, we need the points (0, 6) and (12, 0). Testing the origin (0, 0) satisfies the inequality as 0 + 0 <= 12, showing that the feasible region is the left-below area of